If 1 text{ ampere} electric current passes th | vedclass

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(B) The formula for electric current is $I = Q / t$,where $I$ is current,$Q$ is total charge,and $t$ is time.Given $I = 1 	ext{ A}$ and $t = 1 	ext{

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$6.25 	imes 10^{18}$

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(B) The formula for electric current is $I = Q / t$,where $I$ is current,$Q$ is total charge,and $t$ is time.Given $I = 1 	ext{ A}$ and $t = 1 	ext{ s}$,the total charge $Q = I 	imes t = 1 	ext{ A} 	imes 1 	ext{ s} = 1 	ext{ C}$.The quantization of charge is given by $Q = n 	imes e$,where $n$ is the number of electrons and $e$ is the elementary charge $(e \approx 1.6 	imes 10^{-19} 	ext{ C})$.To find $n$,we rearrange the formula: $n = Q / e$.Substituting the values: $n = 1 	ext{ C} / (1.6 	imes 10^{-19} 	ext{ C}) = 0.625 	imes 10^{19} = 6.25 	imes 10^{18}$.Therefore,$6.25 	imes 10^{18}$ electrons pass through the conductor per second.

If $1 \text{ ampere}$ electric current passes through a conductor,how many electrons will pass per second?

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