If [H_3O^+] = 10^{-6} M in an aqueous soluti | vedclass

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(B) The $pH$ of a solution is defined by the formula: $pH = -\log_{10}[H_3O^+]$.Given that $[H_3O^+] = 10^{-6} \ M$.Substituting the value into the fo

Vedclass · Accepted Answer

$6$

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(B) The $pH$ of a solution is defined by the formula: $pH = -\log_{10}[H_3O^+]$.Given that $[H_3O^+] = 10^{-6} \ M$.Substituting the value into the formula:$pH = -\log_{10}(10^{-6})$.Using the logarithmic property $\log(a^b) = b \cdot \log(a)$:$pH = -(-6) \cdot \log_{10}(10)$.Since $\log_{10}(10) = 1$,we get:$pH = 6$.Therefore,the $pH$ of the solution is $6$.

If $[H_3O^+] = 10^{-6} \ M$ in an aqueous solution,what is the $pH$ of the solution?

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