If {N_a} = {an : n in N},then {N_5} cap {N_7} | vedclass

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(C) The set ${N_a}$ consists of all multiples of $a$,i.e.,${N_a} = \{a, 2a, 3a, \dots\}$.The intersection ${N_5} \cap {N_7}$ consists of numbers that

Vedclass · Accepted Answer

${N_{35}}$

Vedclass · Answer

(C) The set ${N_a}$ consists of all multiples of $a$,i.e.,${N_a} = \{a, 2a, 3a, \dots\}$.The intersection ${N_5} \cap {N_7}$ consists of numbers that are multiples of both $5$ and $7$.Since $5$ and $7$ are relatively prime,the least common multiple of $5$ and $7$ is $5 	imes 7 = 35$.Therefore,the common multiples are multiples of $35$,which is represented as ${N_{35}}$.

If ${N_a} = \{an : n \in N\}$,then ${N_5} \cap {N_7} = $

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