(B) The $HCF$ of two numbers always divides their $LCM$ completely.Given $HCF(a, b) = 16$.We check each option to see if it is divisible by $16$:$A) 3

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(B) The $HCF$ of two numbers always divides their $LCM$ completely.Given $HCF(a, b) = 16$.We check each option to see if it is divisible by $16$:$A) 32 / 16 = 2$ (Divisible)$B) 72 / 16 = 4.5$ (Not divisible)$C) 64 / 16 = 4$ (Divisible)$D) 96 / 16 = 6$ (Divisible)Since $72$ is not divisible by $16$,it cannot be the $LCM$ of $a$ and $b$.

Class 10 Mathematics Real Numbers HCF and LCM by Prime Factorisation

Medium

If $HCF(a, b) = 16$,then which of the following cannot be the $LCM(a, b)$?

A
$32$
B
$72$
C
$64$
D
$96$

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Real Numbers

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HCF and LCM by Prime Factorisation

If $p$ and $q$ are distinct prime integers,then their Least Common Multiple $(LCM)$ is . . . . . . .

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If $k_{1}$ and $k_{2}$ are two distinct prime integers,then their $\text{l.c.m.}$ is ..........

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Using Euclid's division algorithm,find the largest number that divides $1251, 9377$ and $15628$ leaving remainders $1, 2$ and $3$,respectively.

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Find the largest number which divides $615$ and $963$ leaving remainder $6$ in each case.

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Find the $HCF$ and $LCM$ of the integers $8$,$9$,and $25$ by the prime factorization method.

Medium

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If $HCF(a, b) = 16$,then which of the following cannot be the $LCM(a, b)$?

Similar Questions

If $p$ and $q$ are distinct prime integers,then their Least Common Multiple $(LCM)$ is . . . . . . .

If $k_{1}$ and $k_{2}$ are two distinct prime integers,then their $\text{l.c.m.}$ is ..........

Using Euclid's division algorithm,find the largest number that divides $1251, 9377$ and $15628$ leaving remainders $1, 2$ and $3$,respectively.

Find the largest number which divides $615$ and $963$ leaving remainder $6$ in each case.

Find the $HCF$ and $LCM$ of the integers $8$,$9$,and $25$ by the prime factorization method.

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