If $n$ is the number of ways five different employees can sit into four indistinguishable offices where any office may have any number of persons including zero,then $n$ is equal to:

  • A
    $47$
  • B
    $53$
  • C
    $51$
  • D
    $43$

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$I$. The number of positive integral solutions of $x_1+x_2+x_3+x_4=10$ is $286$.
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