If varepsilon_0 is the permittivity of free s | vedclass

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(B) The energy density $u$ of an electric field is given by the formula $u = \frac{1}{2} \varepsilon_0 E^2$.Energy density is defined as energy per un

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$[M L^{-1} T^{-2}]$

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(B) The energy density $u$ of an electric field is given by the formula $u = \frac{1}{2} \varepsilon_0 E^2$.Energy density is defined as energy per unit volume.The dimensions of energy are $[M L^2 T^{-2}]$ and the dimensions of volume are $[L^3]$.Therefore,the dimensions of energy density are $\frac{[M L^2 T^{-2}]}{[L^3]} = [M L^{-1} T^{-2}]$.Since $\varepsilon_0 E^2$ is proportional to energy density,it shares the same dimensions.Thus,the dimensions of $\varepsilon_0 E^2$ are $[M L^{-1} T^{-2}]$.

If $\varepsilon_0$ is the permittivity of free space and $E$ is the electric field,then $\varepsilon_0 E^2$ has the dimensions

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