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(C) The reaction between aniline $(C_6H_5NH_2)$ and benzenediazonium chloride $(C_6H_5N_2^+Cl^-)$ is an electrophilic substitution reaction (coupling

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$591$

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(C) The reaction between aniline $(C_6H_5NH_2)$ and benzenediazonium chloride $(C_6H_5N_2^+Cl^-)$ is an electrophilic substitution reaction (coupling reaction) that produces $p$-aminoazobenzene (aniline yellow).The molar mass of aniline $(C_6H_5NH_2)$ is $93 \ g/mol$.The number of moles of aniline given is $n = \frac{279 \ g}{93 \ g/mol} = 3 \ mol$.Since the reaction is with one equivalent of benzenediazonium chloride,and assuming complete conversion,$3 \ moles$ of aniline will produce $3 \ moles$ of aniline yellow $(C_{12}H_{11}N_3)$.The molar mass of aniline yellow $(C_{12}H_{11}N_3)$ is $(12 	imes 12) + (11 	imes 1) + (3 	imes 14) = 144 + 11 + 42 = 197 \ g/mol$.The mass of aniline yellow formed is $3 \ mol 	imes 197 \ g/mol = 591 \ g$.

If $279 \ g$ of aniline is reacted with one equivalent of benzenediazonium chloride,the maximum amount of aniline yellow formed will be $.........$ $g$. (nearest integer)
(consider complete conversion)

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If $279 \ g$ of aniline is reacted with one equivalent of benzenediazonium chloride,the maximum amount of aniline yellow formed will be $.........$ $g$. (nearest integer)(consider complete conversion)