If $0 < \text{amp}(z) < \pi$,then $\text{amp}(z) - \text{amp}(-z) = $

If $z = \frac{(2-i)(1+i)^3}{(1-i)^2}$,then $\operatorname{Arg}(z) = $

Let $z_1$ and $z_2$ be two complex numbers with $\alpha$ and $\beta$ as their principal arguments such that $\alpha + \beta > \pi$,then the principal argument of $z_1 z_2$ is given by:

If $Z = \frac{-2}{1 + \sqrt{3}i}$,where $i = \sqrt{-1}$,then the value of $\arg(Z)$ is

Convert the given complex number in polar form: $\sqrt{3}+i$

Find the modulus and the argument of the complex number $z = -1 - i \sqrt{3}$.