If $\alpha$ and $\beta$ are the roots of the equation $x^2 + 2x + 4 = 0$,then $\frac{1}{\alpha^3} + \frac{1}{\beta^3}$ is equal to

  • A
    $-\frac{1}{2}$
  • B
    $\frac{1}{2}$
  • C
    $32$
  • D
    $\frac{1}{4}$

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