If $f(x) = \begin{cases} 6 \beta - 3 \alpha x, & \text{if } -4 \leq x < -2 \\ 4x + 1, & \text{if } -2 \leq x \leq 2 \end{cases}$ is continuous on $[-4, 2]$,then $\alpha + \beta = $

  • A
    $\frac{-7}{6}$
  • B
    $\frac{4}{7}$
  • C
    $\frac{-4}{7}$
  • D
    $\frac{7}{6}$

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