If $f(x) = \begin{cases} x \sin \frac{1}{x}, & x \neq 0 \\ k, & x = 0 \end{cases}$ is continuous at $x = 0$,then the value of $k$ is

  • A
    $1$
  • B
    $-1$
  • C
    $0$
  • D
    $2$

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