If p and q each have truth value F,then the t | vedclass

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(B) Given that $p = F$ and $q = F$.Step $1$: Evaluate $(\sim p \vee q) \leftrightarrow \sim(p \wedge q)$$\sim p = \sim F = T$$\sim p \vee q = T \vee F

Vedclass · Accepted Answer

$T, T$

Vedclass · Answer

(B) Given that $p = F$ and $q = F$.Step $1$: Evaluate $(\sim p \vee q) \leftrightarrow \sim(p \wedge q)$$\sim p = \sim F = T$$\sim p \vee q = T \vee F = T$$p \wedge q = F \wedge F = F$$\sim(p \wedge q) = \sim F = T$Therefore,$(\sim p \vee q) \leftrightarrow \sim(p \wedge q) = T \leftrightarrow T = T$.Step $2$: Evaluate $\sim p \leftrightarrow (p \rightarrow \sim q)$$\sim p = T$$\sim q = \sim F = T$$p$ $\rightarrow \sim q = F$ $\rightarrow T = T$Therefore,$\sim p \leftrightarrow (p \rightarrow \sim q) = T \leftrightarrow T = T$.Thus,the truth values are $T, T$.

If $p$ and $q$ each have truth value $F$,then the truth values of the statement patterns $(\sim p \vee q) \leftrightarrow \sim(p \wedge q)$ and $\sim p \leftrightarrow (p \rightarrow \sim q)$ respectively are

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