If A=left[begin{array}{ll}2 & -2 2 & -3end{a | vedclass

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(A) We know the property of inverse of matrices: $(XY)^{-1} = Y^{-1} X^{-1}$.Applying this property to the given expression:$(B^{-1} A^{-1})^{-1} = (A

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$\left[\begin{array}{ll}-2 & -2 \ -3 & -2\end{array}ight]$

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(A) We know the property of inverse of matrices: $(XY)^{-1} = Y^{-1} X^{-1}$.Applying this property to the given expression:$(B^{-1} A^{-1})^{-1} = (A^{-1})^{-1} (B^{-1})^{-1} = AB$.Now,we calculate the product $AB$:$AB = \left[\begin{array}{ll}2 & -2 \ 2 & -3\end{array}ight] \left[\begin{array}{cc}0 & -1 \ 1 & 0\end{array}ight]$$AB = \left[\begin{array}{ll} (2)(0) + (-2)(1) & (2)(-1) + (-2)(0) \ (2)(0) + (-3)(1) & (2)(-1) + (-3)(0) \end{array}ight]$$AB = \left[\begin{array}{ll} 0 - 2 & -2 + 0 \ 0 - 3 & -2 + 0 \end{array}ight] = \left[\begin{array}{ll} -2 & -2 \ -3 & -2 \end{array}ight]$.

If $A=\left[\begin{array}{ll}2 & -2 \\ 2 & -3\end{array}\right]$ and $B=\left[\begin{array}{cc}0 & -1 \\ 1 & 0\end{array}\right]$,then $(B^{-1} A^{-1})^{-1} = ?$

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