If $y = 1 + \frac{x}{1!} + \frac{x^2}{2!} + \frac{x^3}{3!} + \dots \infty$,then $x = $

  • A
    $\log_e y$
  • B
    $\log_e \frac{1}{y}$
  • C
    $e^y$
  • D
    $e^{-y}$

Explore More

Similar Questions

The coefficient of $x^k$ in the expansion of $\frac{1-2x-x^2}{e^{-x}}$ is

The coefficient of $x^r$ in the expansion of $1 + \frac{a + bx}{1!} + \frac{(a + bx)^2}{2!} + \dots + \frac{(a + bx)^n}{n!} + \dots$ is

$1 + \frac{a - bx}{1!} + \frac{(a - bx)^2}{2!} + \frac{(a - bx)^3}{3!} + \dots \infty = $

$\frac{e^2 + 1}{2e} = $

$\sum_{k=1}^{\infty} \frac{1}{k !} \left(\sum_{n=1}^k 2^{n-1}\right)$ is equal to

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo