If $f(x) = \frac{x+2}{18}$ for $-2 < x < 4$ and $f(x) = 0$ otherwise,is the probability density function (p.d.f.) of a random variable $X$,then the value of $P(|X| < 2)$ is
- A$\frac{5}{9}$
- B$\frac{4}{9}$
- C$\frac{2}{9}$
- D$\frac{1}{9}$
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Let $X$ be the discrete random variable representing the number $(x)$ that appears on the face of a biased die when it is rolled. The probability distribution of $X$ is given by:
$X = x$ $1$ $2$ $3$ $4$ $5$ $6$ $P(X = x)$ $0.1$ $0.15$ $0.3$ $0.25$ $k$ $k$
Find the variance of $X$.
| $X = x$ | $1$ | $2$ | $3$ | $4$ | $5$ | $6$ |
| $P(X = x)$ | $0.1$ | $0.15$ | $0.3$ | $0.25$ | $k$ | $k$ |
Find the variance of $X$.
Two numbers are selected at random,without replacement from the first $6$ positive integers. Let $X$ denote the larger of the two numbers. Then $E(X) = $
$A$ fair die is tossed repeatedly until a six is obtained. Let $X$ denote the number of tosses required and let $a=P(X=3)$,$b=P(X \geq 3)$ and $c=P(X \geq 6 \mid X>3)$. Then $\frac{b+c}{a}$ is equal to
DifficultJEE MAIN 2024
View Solution$A$ coin is biased so that the head is $3$ times as likely to occur as tail. This coin is tossed until a head or three tails occur. If $X$ denotes the number of tosses of the coin,then the mean of $X$ is
Two dice are rolled. If a random variable $X$ is defined as the absolute difference of the two numbers that appear on them, then the mean of $X$ is
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