If theta = frac{17 pi}{3},then (tan theta - c | vedclass

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(D) Given $	heta = \frac{17 \pi}{3} = 5 \pi + \frac{2 \pi}{3}$.Since $	an(n \pi + x) = 	an x$ and $\cot(n \pi + x) = \cot x$,we have $	an 	heta =

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$-\frac{2}{\sqrt{3}}$

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(D) Given $	heta = \frac{17 \pi}{3} = 5 \pi + \frac{2 \pi}{3}$.Since $	an(n \pi + x) = 	an x$ and $\cot(n \pi + x) = \cot x$,we have $	an 	heta = 	an \frac{2 \pi}{3} = -\sqrt{3}$ and $\cot 	heta = \cot \frac{2 \pi}{3} = -\frac{1}{\sqrt{3}}$.Now,calculate $(	an 	heta - \cot 	heta) = -\sqrt{3} - (-\frac{1}{\sqrt{3}})$.$= -\sqrt{3} + \frac{1}{\sqrt{3}} = \frac{-3 + 1}{\sqrt{3}} = \frac{-2}{\sqrt{3}}$.

If $\theta = \frac{17 \pi}{3}$,then $(\tan \theta - \cot \theta) = \dots$

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