If tan A = frac{5}{6} and tan B = frac{1}{11} | vedclass

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(D) We use the formula for the tangent of the sum of two angles: $	an(A+B) = \frac{	an A + 	an B}{1 - 	an A 	an B}$.Substituting the given values

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$\frac{\pi}{4}$

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(D) We use the formula for the tangent of the sum of two angles: $	an(A+B) = \frac{	an A + 	an B}{1 - 	an A 	an B}$.Substituting the given values: $	an(A+B) = \frac{\frac{5}{6} + \frac{1}{11}}{1 - (\frac{5}{6} 	imes \frac{1}{11})}$.Simplifying the numerator: $\frac{5}{6} + \frac{1}{11} = \frac{55 + 6}{66} = \frac{61}{66}$.Simplifying the denominator: $1 - \frac{5}{66} = \frac{66 - 5}{66} = \frac{61}{66}$.Thus,$	an(A+B) = \frac{61/66}{61/66} = 1$.Since $	an(A+B) = 1$,we have $A+B = 	an^{-1}(1) = \frac{\pi}{4}$.

If $\tan A = \frac{5}{6}$ and $\tan B = \frac{1}{11}$,then $A + B = $

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