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(B) Given the matrix equation: $\begin{bmatrix} x & 0 \ 1 & y \end{bmatrix} + \begin{bmatrix} -2 & 1 \ 3 & 4 \end{bmatrix} = \begin{bmatrix} 3 & 5 \

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$x = 3, y = -2$

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(B) Given the matrix equation: $\begin{bmatrix} x & 0 \ 1 & y \end{bmatrix} + \begin{bmatrix} -2 & 1 \ 3 & 4 \end{bmatrix} = \begin{bmatrix} 3 & 5 \ 6 & 3 \end{bmatrix} - \begin{bmatrix} 2 & 4 \ 2 & 1 \end{bmatrix}$ First,perform the addition on the left side: $\begin{bmatrix} x - 2 & 0 + 1 \ 1 + 3 & y + 4 \end{bmatrix} = \begin{bmatrix} x - 2 & 1 \ 4 & y + 4 \end{bmatrix}$ Next,perform the subtraction on the right side: $\begin{bmatrix} 3 - 2 & 5 - 4 \ 6 - 2 & 3 - 1 \end{bmatrix} = \begin{bmatrix} 1 & 1 \ 4 & 2 \end{bmatrix}$ Equating the corresponding elements of the two matrices: $x - 2 = 1 \Rightarrow x = 3$ $y + 4 = 2 \Rightarrow y = -2$ Thus,the values are $x = 3$ and $y = -2$.

If $\begin{bmatrix} x & 0 \\ 1 & y \end{bmatrix} + \begin{bmatrix} -2 & 1 \\ 3 & 4 \end{bmatrix} = \begin{bmatrix} 3 & 5 \\ 6 & 3 \end{bmatrix} - \begin{bmatrix} 2 & 4 \\ 2 & 1 \end{bmatrix}$,then find the values of $x$ and $y$.

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