If sin x = -frac{24}{25}, then the value of t | vedclass

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(B) Given $\sin x = -\frac{24}{25}$.Since $\sin^2 x + \cos^2 x = 1$,we have $\cos^2 x = 1 - \sin^2 x$.$\cos^2 x = 1 - \left(-\frac{24}{25}\right)^2 =

Vedclass · Accepted Answer

$-\frac{24}{7}$

Vedclass · Answer

(B) Given $\sin x = -\frac{24}{25}$.Since $\sin^2 x + \cos^2 x = 1$,we have $\cos^2 x = 1 - \sin^2 x$.$\cos^2 x = 1 - \left(-\frac{24}{25}ight)^2 = 1 - \frac{576}{625} = \frac{625 - 576}{625} = \frac{49}{625}$.Thus,$\cos x = \pm \frac{7}{25}$.Since $	an x = \frac{\sin x}{\cos x}$,if $\cos x = \frac{7}{25}$,then $	an x = \frac{-24/25}{7/25} = -\frac{24}{7}$.If $\cos x = -\frac{7}{25}$,then $	an x = \frac{-24/25}{-7/25} = \frac{24}{7}$.Given the options,the correct value is $-\frac{24}{7}$.

If $\sin x = -\frac{24}{25},$ then the value of $\tan x$ is

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