If pi

Question

(B) Given expression: $E = \sqrt{\frac{1 - \cos \alpha}{1 + \cos \alpha}} + \sqrt{\frac{1 + \cos \alpha}{1 - \cos \alpha}}$Taking the common denominat

Vedclass · Accepted Answer

$-\frac{2}{\sin \alpha}$

Vedclass · Answer

(B) Given expression: $E = \sqrt{\frac{1 - \cos \alpha}{1 + \cos \alpha}} + \sqrt{\frac{1 + \cos \alpha}{1 - \cos \alpha}}$Taking the common denominator: $E = \frac{(1 - \cos \alpha) + (1 + \cos \alpha)}{\sqrt{(1 + \cos \alpha)(1 - \cos \alpha)}}$Simplifying the numerator and denominator: $E = \frac{2}{\sqrt{1 - \cos^2 \alpha}} = \frac{2}{\sqrt{\sin^2 \alpha}} = \frac{2}{|\sin \alpha|}$Since $\pi Therefore,$|\sin \alpha| = -\sin \alpha$.Thus,$E = \frac{2}{-\sin \alpha} = -\frac{2}{\sin \alpha}$.

If $\pi < \alpha < \frac{3\pi}{2}$,then $\sqrt{\frac{1 - \cos \alpha}{1 + \cos \alpha}} + \sqrt{\frac{1 + \cos \alpha}{1 - \cos \alpha}} = $

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