If $A = \begin{bmatrix} 1 & -1 & 1 \\ 2 & 1 & -3 \\ 1 & 1 & 1 \end{bmatrix}$,$10B = \begin{bmatrix} 4 & 2 & 2 \\ -5 & 0 & \alpha \\ 1 & -2 & 3 \end{bmatrix}$ and $B$ is the inverse of matrix $A$,then $\alpha$ is equal to . . . . . . .

  • A
    $3$
  • B
    $9$
  • C
    $5$
  • D
    $10$

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