If $A = \begin{bmatrix} 8 & -2 \\ -4 & 1 \end{bmatrix}$ is given,then $A^{-1}$ is:
- A$\begin{bmatrix} 1 & 2 \\ 4 & 8 \end{bmatrix}$
- B$\begin{bmatrix} \frac{1}{16} & \frac{2}{16} \\ \frac{4}{16} & \frac{8}{16} \end{bmatrix}$
- C$\begin{bmatrix} \frac{1}{16} & -\frac{1}{8} \\ -\frac{1}{4} & \frac{1}{2} \end{bmatrix}$
- DDoes not exist.
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