If $P(A) = \frac{6}{11}$,$P(B) = \frac{5}{11}$ and $P(A \cup B) = \frac{7}{11}$,then $P(A \mid B) = $ . . . . . . .

  • A
    $\frac{4}{5}$
  • B
    $\frac{4}{11}$
  • C
    $\frac{2}{3}$
  • D
    $\frac{2}{11}$

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