If $2 P(A) = P(B) = \frac{5}{13}$ and $P(A \mid B) = \frac{2}{5}$,then $P(A \cup B) = $ . . . . . . .

  • A
    $\frac{10}{26}$
  • B
    $\frac{10}{13}$
  • C
    $\frac{11}{26}$
  • D
    $\frac{11}{13}$

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List-$I$List-$II$
$A$. $P(\frac{A}{B})$$(i)$. $\frac{2}{15}$
$B$. $P(\bar{B})$$(ii)$. $\frac{4}{15}$
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$(v)$. $\frac{3}{7}$

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