If tan frac{theta}{2} = t,then frac{1 - t^2}{ | vedclass

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(A) Given that $	an \frac{	heta}{2} = t$.We know the standard trigonometric identity for $\cos 	heta$ in terms of $	an \frac{	heta}{2}$ is:$\cos

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$\cos 	heta$

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(A) Given that $	an \frac{	heta}{2} = t$.We know the standard trigonometric identity for $\cos 	heta$ in terms of $	an \frac{	heta}{2}$ is:$\cos 	heta = \frac{1 - 	an^2 \frac{	heta}{2}}{1 + 	an^2 \frac{	heta}{2}}$.Substituting $t = 	an \frac{	heta}{2}$ into the identity:$\cos 	heta = \frac{1 - t^2}{1 + t^2}$.Therefore,the expression $\frac{1 - t^2}{1 + t^2}$ is equal to $\cos 	heta$.

If $\tan \frac{\theta}{2} = t$,then $\frac{1 - t^2}{1 + t^2}$ is equal to

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