If $5 \ g$ $NaOH$ is dissolved in $450 \ mL$ of solution,the molarity of the solution is: $(Na=23, O=16, H=1 \ g \ mol^{-1})$ (in $M$)

Calculate the mass of sodium acetate $(CH_3COONa)$ required to make $500 \ mL$ of a $0.375 \ M$ aqueous solution. The molar mass of sodium acetate is $82.0245 \ g \ mol^{-1}$. (in $g$)

The density of liquid $HCl$ is $1.17 \ g/cm^3$. What is its molarity?

$V_1 \ \text{c.c.}$ of a solution having molarity $M_1$ is diluted to have molarity $M_2$. The volume of water required to be added will be $:-$

The volume of a solution changes with a change in temperature. How will the molality of the solution be affected by temperature? Give a reason for your answer.

When the concentration is expressed as the number of moles of a solute per litre of solution,it is known as: