If 2tan^2 theta = sec^2 theta,then the genera | vedclass

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(C) Given the equation: $2	an^2 	heta = \sec^2 	heta$Using the identity $\sec^2 	heta = 1 + 	an^2 	heta$,we get:$2	an^2 	heta = 1 + 	an^2 	h

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$n\pi \pm \frac{\pi}{4}$

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(C) Given the equation: $2	an^2 	heta = \sec^2 	heta$Using the identity $\sec^2 	heta = 1 + 	an^2 	heta$,we get:$2	an^2 	heta = 1 + 	an^2 	heta$Subtracting $	an^2 	heta$ from both sides:$	an^2 	heta = 1$This can be written as:$	an^2 	heta = 	an^2 \left(\frac{\pi}{4}ight)$For $	an^2 	heta = 	an^2 \alpha$,the general solution is $	heta = n\pi \pm \alpha$.Therefore,$	heta = n\pi \pm \frac{\pi}{4}$.

If $2\tan^2 \theta = \sec^2 \theta$,then the general value of $\theta$ is

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