If frac{1 - cos 2theta}{1 + cos 2theta} = 3,t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given the equation: $\frac{1 - \cos 2	heta}{1 + \cos 2	heta} = 3$Using the trigonometric identities $\cos 2	heta = 1 - 2\sin^2 	heta$ and $\co

Vedclass · Accepted Answer

$n\pi \pm \frac{\pi}{3}$

Vedclass · Answer

(D) Given the equation: $\frac{1 - \cos 2	heta}{1 + \cos 2	heta} = 3$Using the trigonometric identities $\cos 2	heta = 1 - 2\sin^2 	heta$ and $\cos 2	heta = 2\cos^2 	heta - 1$,we get:$\frac{1 - (1 - 2\sin^2 	heta)}{1 + (2\cos^2 	heta - 1)} = 3$$\frac{2\sin^2 	heta}{2\cos^2 	heta} = 3$$	an^2 	heta = 3$$	an^2 	heta = (\sqrt{3})^2 = 	an^2(\frac{\pi}{3})$The general solution for $	an^2 	heta = 	an^2 \alpha$ is $	heta = n\pi \pm \alpha$.Therefore,$	heta = n\pi \pm \frac{\pi}{3}$.

If $\frac{1 - \cos 2\theta}{1 + \cos 2\theta} = 3$,then the general value of $\theta$ is

Similar Questions

The general solution of the equation $\tan^2 x = 1$ is

If $0 \leq x \leq 2 \pi$,then the number of real values of $x$ which satisfy the equation $\sin x + \sin 2x + \sin 3x + \sin 4x = 0$ is

If $\sin \theta = \sin \alpha$,then $\sin \frac{\theta}{3}$ is equal to:

If $\cos(\alpha - \beta) = 1$ and $\cos(\alpha + \beta) = \frac{1}{e}$,where $-\pi < \alpha, \beta < \pi$,then the total number of ordered pairs $(\alpha, \beta)$ is:

The solution set of the trigonometric equation $\tan \theta + 5 \cot \theta = \sec \theta$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module