If f: R rightarrow R is defined by f(x)=|x|,t | vedclass

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(C) We have $f(x) = |x|$.For a function to be invertible,it must be both one-one (injective) and onto (surjective).Consider the values $f(1) = |1| = 1

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the function $f^{-1}(x)$ does not exist

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(C) We have $f(x) = |x|$.For a function to be invertible,it must be both one-one (injective) and onto (surjective).Consider the values $f(1) = |1| = 1$ and $f(-1) = |-1| = 1$.Since $f(1) = f(-1)$ but $1 
eq -1$,the function is not one-one.Because the function is not one-one,it is not bijective.Therefore,the inverse function $f^{-1}(x)$ does not exist.

If $f: R \rightarrow R$ is defined by $f(x)=|x|$,then

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