If $[x]^2-5[x]+6=0$,where $[x]$ denotes the greatest integer function,then

How many positive real numbers $x$ satisfy the equation $x^3-3|x|+2=0$?

The number of elements in the set $\{x \in R : (|x|-3)|x+4|=6\}$ is equal to

Statement $-1$: Any function $f(x)$ is an even function if $f(-x) = f(x)$ for all $x$ in its domain.
Statement $-2$: The function $f(x) = \frac{1}{\sqrt{1 - x^2}} + \left[ \frac{x^2 + x + 1}{4} \right]$,where $[.]$ denotes the greatest integer function,is an even function.

Draw the graph of the function $f: R \rightarrow R$ defined by $f(x) = x^{3}, x \in R$.

Let $[t]$ denote the greatest integer $\leq t$. Then the equation in $x$,$[x]^{2}+2[x+2]-7=0$ has