If $N_2$ gas is bubbled through water at $293 \ K$, how many moles of $N_2$ gas would dissolve in $1 \ litre$ of water? Assume that $N_2$ exerts a partial pressure of $0.987 \ bar$. [Given: $K_{H}$ for $N_2$ at $293 \ K$ is $76.48 \ kbar$]

The solution of sugar in water contains

At $298 \ K$,Henry's law constant for $CO_2$ in water is $1.67 \times 10^8 \ Pa$. At $298 \ K$,the quantity of $CO_2$ in $1000 \ mL$ of soda water when packed at $1.67 \times 10^2 \ kPa$ $CO_2$ pressure in $mol \ L^{-1}$ is: (water density $= 1.0 \ g \ cm^{-3}$)

$A$ company dissolves '$X$' amount of $CO_{2}$ at $298 \ K$ in $1 \ L$ of water to prepare soda water. $X = ........ \ \times 10^{-3} \ g$ (nearest integer).
(Given: partial pressure of $CO_{2}$ at $298 \ K = 0.835 \ bar$.
Henry's law constant for $CO_{2}$ at $298 \ K = 1.67 \ kbar$.
Atomic mass of $H$,$C$ and $O$ is $1$,$12$ and $16 \ g \ mol^{-1}$,respectively.)

Calculate the solubility of a gas having partial pressure $0.15 \ bar$ at $25^{\circ} C$.
$[K_{H} = 0.16 \ mol \ dm^{-3} \ bar^{-1}]$

At $298 \ K$, the mole percentage of $N_{2(g)}$ in air is $80\%$. Water is in equilibrium with air at a pressure of $10 \ atm$. What is the mole fraction of $N_{2(g)}$ in water at $298 \ K$? ($K_H$ for $N_2$ is $6.5 \times 10^7 \ mm \ Hg$)