Easy
If $\gamma$ is the ratio of specific heats and $R$ is the universal gas constant,then the molar specific heat at constant volume $C_{V}$ is given by
- A$\gamma R$
- B$\frac{(\gamma-1) R}{\gamma}$
- C$\frac{R}{\gamma-1}$
- D$\frac{\gamma R}{\gamma-1}$
Explore More
Similar Questions
According to the law of equipartition of energy, the molar specific heat of a diatomic gas at constant volume, where the molecule has one additional vibrational mode, is:
What is the relationship between the internal energy $U$ of an ideal gas and its pressure $P$ and volume $V$?
Medium
View SolutionFor a monoatomic ideal gas,the universal gas constant $R$ is $n$ times the molar heat capacity at constant pressure $C_P$. Here,$n$ is ......
Easy
View SolutionThe total internal energy of $2$ mole monoatomic ideal gas at temperature $T=300\,K$ will be ...........$J$. (Given $R = 8.31\,J/mol\cdot K$)
If the specific heats of a monoatomic gas and a diatomic gas are the same, which relation is valid?
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo