If N_A, N_B,and N_C are the number of signifi | vedclass

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(A) To determine the number of significant figures,we apply the following rules:$(i)$ For $A = 0.001204 \ m$: Leading zeros are not significant. The d

Vedclass · Accepted Answer

$N_A=N_B=N_C$

Vedclass · Answer

(A) To determine the number of significant figures,we apply the following rules:$(i)$ For $A = 0.001204 \ m$: Leading zeros are not significant. The digits $1, 2, 0, 4$ are significant. Thus,$N_A = 4$.$(ii)$ For $B = 43120000 \ m$: Trailing zeros in a number without a decimal point are not significant. The digits $4, 3, 1, 2$ are significant. Thus,$N_B = 4$.$(iii)$ For $C = 1.200 \ m$: Trailing zeros in a number with a decimal point are significant. The digits $1, 2, 0, 0$ are significant. Thus,$N_C = 4$.Since $N_A = 4, N_B = 4$,and $N_C = 4$,we conclude that $N_A = N_B = N_C$.

If $N_A, N_B$,and $N_C$ are the number of significant figures in $A=0.001204 \ m$,$B=43120000 \ m$,and $C=1.200 \ m$ respectively,then:

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