If $\frac{x^2-3x+1}{(x-1)(x-2)(x-3)}=\frac{A}{x-3}+\frac{B}{(x-1)(x-2)}+\frac{C}{(x-1)(x-2)(x-3)}$,then $B=$

  • A
    $0$
  • B
    $1$
  • C
    $-1$
  • D
    $2$

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