If $2, 1, 1$ are roots of the equation $x^3-4x^2+5x-2=0$,then find the roots of the equation $\left(x+\frac{1}{3}\right)^3-4\left(x+\frac{1}{3}\right)^2+5\left(x+\frac{1}{3}\right)-2=0$.

  • A
    $\frac{7}{3}, \frac{4}{3}, \frac{4}{3}$
  • B
    $\frac{5}{3}, \frac{2}{3}, \frac{2}{3}$
  • C
    $\frac{-5}{3}, \frac{-2}{3}, \frac{-2}{3}$
  • D
    $\frac{-7}{3}, \frac{-4}{3}, \frac{-4}{3}$

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