If $\theta$ lies in the first quadrant and $5 \tan \theta = 4$,then $\frac{5 \sin \theta - 3 \cos \theta}{\sin \theta + 2 \cos \theta}$ is equal to

  • A
    $\frac{5}{14}$
  • B
    $\frac{3}{14}$
  • C
    $\frac{1}{14}$
  • D
    $0$

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