(C) Given that $2 \sin 2 \theta = \sqrt{3}$.Dividing both sides by $2$,we get $\sin 2 \theta = \frac{\sqrt{3}}{2}$.We know that $\sin 60^{\circ} = \fr

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(C) Given that $2 \sin 2 \theta = \sqrt{3}$.Dividing both sides by $2$,we get $\sin 2 \theta = \frac{\sqrt{3}}{2}$.We know that $\sin 60^{\circ} = \frac{\sqrt{3}}{2}$,so $\sin 2 \theta = \sin 60^{\circ}$.Comparing the angles,$2 \theta = 60^{\circ}$.Therefore,$\theta = \frac{60^{\circ}}{2} = 30^{\circ}$.

Class 11 Mathematics Trigonometrical Equations Solution of trigonometrical equations

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If $2 \sin 2 \theta = \sqrt{3}$,then $\theta = $ (in $^{\circ}$)

AP EAMCET 2022 All AP EAMCET

A
$15$
B
$27$
C
$30$
D
$40$

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Trigonometrical Equations

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Solution of trigonometrical equations

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If $2 \sin 2 \theta = \sqrt{3}$,then $\theta = $ (in $^{\circ}$)

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