If $\theta$ is the angle between the tangents from $(-1,0)$ to the circle $x^2+y^2-5x+4y-2=0$,then $\theta$ is equal to

  • A
    $2 \tan^{-1}\left(\frac{7}{4}\right)$
  • B
    $\tan^{-1}\left(\frac{7}{4}\right)$
  • C
    $2 \cot^{-1}\left(\frac{7}{4}\right)$
  • D
    $\cot^{-1}\left(\frac{7}{4}\right)$

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