If $(1+x)^{15}=a_0+a_1 x+\ldots+a_{15} x^{15}$,then $\sum_{r=1}^{15} r \frac{a_r}{a_{r-1}}$ is equal to

  • A
    $110$
  • B
    $115$
  • C
    $120$
  • D
    $135$

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