यदि $\lim _{x \rightarrow 0} \frac{e^x-a-\log (1+x)}{\sin x}=0$ है,तो $a=$

  • A
    $2$
  • B
    $0$
  • C
    $-1$
  • D
    $1$

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Similar Questions

माना $\alpha, \beta \in R$ इस प्रकार हैं कि $\lim _{x \rightarrow 0} \frac{x^2 \sin (\beta x)}{\alpha x-\sin x}=1$ है। तब $6(\alpha+\beta)$ का मान ज्ञात कीजिए।

यदि $\lim _{x \rightarrow \infty}\left(\frac{x^2+1}{x+1}-a x-b\right)=0$, जहाँ $a, b \in R$, तो:

यदि $\lim_{x \rightarrow 1} \frac{x+x^{2}+x^{3}+\ldots+x^{n}-n}{x-1}=820, (n \in N)$ है,तो $n$ का मान ज्ञात कीजिए।

यदि $\mathop {\lim }\limits_{x \to \frac{1}{2}} \frac{{a{x^2} + bx + c}}{{{{(2x - 1)}^2}}} = \frac{1}{2}$ है,तो $\mathop {\lim }\limits_{x \to 2} \frac{{(x - a)(x - b)(x - c)}}{{x - 2}}$ का मान ज्ञात कीजिए।

यदि $\alpha, \beta$ समीकरण $ax^2+bx+c=0$ के मूल हैं,तो $\lim_{x \rightarrow \alpha} \frac{1-\cos(ax^2+bx+c)}{(x-\alpha)^2} =$

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