If f : mathbb{Z} rightarrow mathbb{Z} is defi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given,$f(x) = x^{9} - 11 x^{8} - 2 x^{7} + 22 x^{6} + x^{4} - 12 x^{3} + 11 x^{2} + x - 3$. To find $f(11)$,substitute $x = 11$ into the expressio

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(B) Given,$f(x) = x^{9} - 11 x^{8} - 2 x^{7} + 22 x^{6} + x^{4} - 12 x^{3} + 11 x^{2} + x - 3$. To find $f(11)$,substitute $x = 11$ into the expression: $f(11) = 11^{9} - 11(11)^{8} - 2(11)^{7} + 22(11)^{6} + 11^{4} - 12(11)^{3} + 11(11)^{2} + 11 - 3$. Observe the terms: $11^{9} - 11(11)^{8} = 11^{9} - 11^{9} = 0$. $-2(11)^{7} + 22(11)^{6} = -2(11)^{7} + 2(11)(11)^{6} = -2(11)^{7} + 2(11)^{7} = 0$. $11^{4} - 12(11)^{3} + 11(11)^{2} = 11^{4} - 12(11)^{3} + 11^{3} = 11^{4} - 11(11)^{3} = 11^{4} - 11^{4} = 0$. Thus,the expression simplifies to: $f(11) = 0 + 0 + 0 + 11 - 3 = 8$.

If $f : \mathbb{Z} \rightarrow \mathbb{Z}$ is defined by $f(x) = x^{9} - 11 x^{8} - 2 x^{7} + 22 x^{6} + x^{4} - 12 x^{3} + 11 x^{2} + x - 3, \forall x \in \mathbb{Z}$,then $f(11) = $

Similar Questions

The number of real linear functions $f(x)$ satisfying $f(f(x))=x+f(x)$ is

$A$ real-valued function $f(x)$ satisfies the functional equation $f(x - y) = f(x)f(y) - f(a - x)f(a + y)$,where $a$ is a given constant and $f(0) = 1$. Then $f(2a - x)$ is equal to:

$A$ real valued function $y = f(x)$ satisfies the relation $f\left( x - \frac{4}{9} \right) + 2x \le \frac{9}{4}x^2 + \frac{8}{9} \le f\left( x + \frac{4}{9} \right) - 2x$. The value of $f''(2)$ is

Let $f$ be a function such that $3f(x) + 2f\left(\frac{m}{19x}\right) = 5x$, $x \neq 0$, where $m = \sum_{i=1}^9 (i)^2$. Then $f(5) - f(2)$ is equal to

Let $f$ be a function such that $f(x) + 3f\left(\frac{24}{x}\right) = 4x$,where $x \neq 0$. Then $f(3) + f(8)$ is equal to:

Vedclass Test Series

Exam Paper Generator

Online Exam Module