If 0.5 mol of a metal forms a hexagonal clos | vedclass

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Question

(A) In a close-packed structure,if the number of atoms is $N$,then the number of octahedral voids is $N$ and the number of tetrahedral voids is $2N$.

Vedclass · Accepted Answer

$1.5, 1.0$

Vedclass · Answer

(A) In a close-packed structure,if the number of atoms is $N$,then the number of octahedral voids is $N$ and the number of tetrahedral voids is $2N$. Given,number of moles of metal atoms $= 0.5 \ mol$. Number of octahedral voids $= 0.5 \ mol$. Number of tetrahedral voids $= 2 	imes 0.5 \ mol = 1.0 \ mol$. Total number of voids $= 	ext{octahedral voids} + 	ext{tetrahedral voids} = 0.5 \ mol + 1.0 \ mol = 1.5 \ mol$. Thus,the total number of voids is $1.5 \ mol$ and the number of tetrahedral voids is $1.0 \ mol$. Therefore,option $(A)$ is the correct answer.

If $0.5 \ mol$ of a metal forms a hexagonal close-packed structure,the total number of voids and tetrahedral voids respectively in $mol$ are

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