If a 0 and b^2 - 4ac = 0,then the curve y = | vedclass

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(D) Given the quadratic expression $y = ax^2 + bx + c$. Since $a > 0$,the parabola opens upwards. The discriminant $D = b^2 - 4ac = 0$ implies that th

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touches the $x$-axis and lies above it

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(D) Given the quadratic expression $y = ax^2 + bx + c$. Since $a > 0$,the parabola opens upwards. The discriminant $D = b^2 - 4ac = 0$ implies that the quadratic equation $ax^2 + bx + c = 0$ has two equal real roots. This means the curve touches the $x$-axis at exactly one point. Since $a > 0$,the vertex of the parabola is at its minimum value,which is $0$ on the $x$-axis,and the rest of the curve lies above the $x$-axis. Therefore,the curve touches the $x$-axis and lies above it.

If $a > 0$ and $b^2 - 4ac = 0$,then the curve $y = ax^2 + bx + c$

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