If 3 sisters and 8 other girls are together p | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Total number of girls $= 3 + 8 = 11$. Number of ways to arrange $11$ girls around a circle is $(11 - 1)! = 10!$. To find the number of ways where

Vedclass · Accepted Answer

$8 ! 	imes 84$

Vedclass · Answer

(D) Total number of girls $= 3 + 8 = 11$. Number of ways to arrange $11$ girls around a circle is $(11 - 1)! = 10!$. To find the number of ways where the $3$ sisters are $NOT$ seated together,we use the complement method: Total arrangements $-$ Arrangements where $3$ sisters are together. Treating the $3$ sisters as a single unit,we have $8 + 1 = 9$ units to arrange in a circle,which can be done in $(9 - 1)! = 8!$ ways. The $3$ sisters can be arranged among themselves in $3!$ ways. So,arrangements where $3$ sisters are together $= 8! 	imes 3!$. Required number of ways $= 10! - (8! 	imes 3!) = 10! - (8! 	imes 6)$. $= 8! 	imes (10 	imes 9 - 6) = 8! 	imes (90 - 6) = 8! 	imes 84$.

If $3$ sisters and $8$ other girls are together playing a game,then the number of ways in which all the girls are seated around a circle such that the three sisters are not seated together,is

Similar Questions

If seven women and seven men are to be seated around a circular table such that there is a man on either side of every woman,then the number of seating arrangements is

The number of different ways of preparing a garland by using $6$ distinct white roses and $6$ distinct red roses such that no two red roses come together is

In how many ways can $4$ beads be selected and arranged in a necklace from $6$ distinct beads?

$4$ gentlemen and $4$ ladies are to be seated at a round table. What is the probability that they sit alternately?

The number of ways in which $6$ boys and $5$ girls can sit at a round table,if no two girls are to sit together,is

Vedclass Test Series

Exam Paper Generator

Online Exam Module