If $1^{\circ} = \alpha$ radians,then the approximate value of $\cos(60^{\circ} 1^{\prime})$ is

  • A
    $\frac{1}{2} + \frac{\alpha \sqrt{3}}{120}$
  • B
    $\frac{1}{2} - \frac{\alpha}{120}$
  • C
    $\frac{1}{2} - \frac{\alpha \sqrt{3}}{120}$
  • D
    $\frac{1}{2} + \frac{\alpha}{120}$

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