If $\bar{x}$ is the mean of $n$ observations $x_1, x_2, \ldots, x_n$,then the mean of the absolute deviations of these observations from $\bar{x}$ is
- Athe variance of the data
- Bthe mean proportion of the data
- Cthe standard deviation of the data
- Dthe mean deviation of the data
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Similar Questions
If $10$ is the mean deviation of $n$ observations $x_1, x_2, x_3, \ldots, x_n$,then the mean deviation of the observations $\frac{2x_1+5}{3}, \frac{2x_2+5}{3}, \frac{2x_3+5}{3}, \ldots, \frac{2x_n+5}{3}$ is
The mean deviation of the numbers $a, a+d, a+2d, \ldots, a+2nd$ from their mean is equal to
Find the mean deviation about the mean for the following data:
Marks obtained $0-20$ $20-40$ $40-60$ $60-80$ $80-100$ Number of students $10$ $8$ $12$ $9$ $11$
| Marks obtained | $0-20$ | $20-40$ | $40-60$ | $60-80$ | $80-100$ |
| Number of students | $10$ | $8$ | $12$ | $9$ | $11$ |
Find the mean deviation about the median for the following data: $3, 9, 5, 3, 12, 10, 18, 4, 7, 19, 21$ (in $.27$)
Medium
View SolutionCalculate the mean deviation about the median age for the age distribution of $100$ persons given below:
Age (in years) $16-20$ $21-25$ $26-30$ $31-35$ $36-40$ $41-45$ $46-50$ $51-55$ Number of persons $5$ $6$ $12$ $14$ $26$ $12$ $16$ $9$
| Age (in years) | $16-20$ | $21-25$ | $26-30$ | $31-35$ | $36-40$ | $41-45$ | $46-50$ | $51-55$ |
| Number of persons | $5$ | $6$ | $12$ | $14$ | $26$ | $12$ | $16$ | $9$ |
Difficult
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