If $f(x) = \begin{cases} [x], & -3 < x \leq -1 \\ |x|, & -1 < x < 1 \\ |[x]|, & 1 \leq x < 3 \end{cases}$ then the set $\{x : f(x) \geq 0\}$ is equal to
- A$(-1, 3)$
- B$[-1, 3)$
- C$(-1, 3]$
- D$[0, 3)$
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