If $a \cdot \hat{i} = a \cdot (\hat{i} + \hat{j}) = a \cdot (\hat{i} + \hat{j} + \hat{k})$, then $a$ is equal to

  • A
    $\hat{i}$
  • B
    $\hat{j}$
  • C
    $\hat{k}$
  • D
    $\hat{i} + \hat{j} + \hat{k}$

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