If $a$ and $b$ are arbitrary positive real numbers, then the least possible value of $\frac{6a}{5b} + \frac{10b}{3a}$ is

  • A
    $4$
  • B
    $\frac{6}{5}$
  • C
    $\frac{10}{3}$
  • D
    $\frac{68}{15}$

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