If $f(x) = \begin{cases} \frac{\sin 2x}{5x}, & x \ne 0 \\ k, & x = 0 \end{cases}$ is continuous at $x = 0$,then the value of $k$ will be

  • A
    $1$
  • B
    $\frac{2}{5}$
  • C
    $-\frac{2}{5}$
  • D
    None of these

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